5y^2+14y+8=0

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Solution for 5y^2+14y+8=0 equation: 



5y^2+14y+8=0

a = 5; b = 14; c = +8;
Δ = b2-4ac
Δ = 142-4·5·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6}{2*5}=\frac{-20}{10}
=-2
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6}{2*5}=\frac{-8}{10}
=-4/5
$

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